Electro Magnetic Induction And Alternating Currents Question 579

Question: A coil of resistance 10 W and an inductance 5H is connected to a 100 volt battery. Then energy stored in the coil is [Pb. PMT 2001; CPMT 2002]

Options:

A) 125 erg

B) 125 J

C) 250 erg

D) 250 J

Show Answer

Answer:

Correct Answer: D

Solution:

$ U=\frac{1}{2}Li^{2}\Rightarrow U=\frac{1}{2}\times 5\times {{( \frac{100}{10} )}^{2}}=250J $



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