Electro Magnetic Induction And Alternating Currents Question 579
Question: A coil of resistance 10 W and an inductance 5H is connected to a 100 volt battery. Then energy stored in the coil is [Pb. PMT 2001; CPMT 2002]
Options:
A) 125 erg
B) 125 J
C) 250 erg
D) 250 J
Show Answer
Answer:
Correct Answer: D
Solution:
$ U=\frac{1}{2}Li^{2}\Rightarrow U=\frac{1}{2}\times 5\times {{( \frac{100}{10} )}^{2}}=250J $
