Electro Magnetic Induction And Alternating Currents Question 572

Question: The inductance of a closed-packed coil of 400 turns is 8 mH. A current of 5 mA is passed through it. The magnetic flux through each turn of the coil is [Roorkee 2000]

Options:

A) $ \frac{1}{4\pi },{\mu_{0}}Wb $

B) $ \frac{1}{2\pi } $ m0Wb

C) $ \frac{1}{3\pi }{\mu_{0}}Wb $

D) $ 0.4,{\mu_{0}}Wb $

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Answer:

Correct Answer: A

Solution:

$ N\varphi =Li\Rightarrow \varphi =\frac{Li}{N}=\frac{8\times {{10}^{-3}}\times 5\times {{10}^{-3}}}{400}={{10}^{-7}}=\frac{{\mu_{0}}}{4\pi }wb $



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