Electro Magnetic Induction And Alternating Currents Question 572
Question: The inductance of a closed-packed coil of 400 turns is 8 mH. A current of 5 mA is passed through it. The magnetic flux through each turn of the coil is [Roorkee 2000]
Options:
A) $ \frac{1}{4\pi },{\mu_{0}}Wb $
B) $ \frac{1}{2\pi } $ m0Wb
C) $ \frac{1}{3\pi }{\mu_{0}}Wb $
D) $ 0.4,{\mu_{0}}Wb $
Show Answer
Answer:
Correct Answer: A
Solution:
$ N\varphi =Li\Rightarrow \varphi =\frac{Li}{N}=\frac{8\times {{10}^{-3}}\times 5\times {{10}^{-3}}}{400}={{10}^{-7}}=\frac{{\mu_{0}}}{4\pi }wb $
