Electro Magnetic Induction And Alternating Currents Question 564

Question: A 100 mH coil carries a current of 1 ampere. Energy stored in its magnetic field is [CBSE PMT 1992; KCET 1998]

Options:

A) 0.5 J

B) 1 J

C) 0.05 J

D) 0.1 J

Show Answer

Answer:

Correct Answer: C

Solution:

Energy $ =\frac{1}{2}LI^{2}=\frac{1}{2}\times 100\times {{10}^{-3}}\times 1^{2}=0.05J $



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