Electro Magnetic Induction And Alternating Currents Question 564
Question: A 100 mH coil carries a current of 1 ampere. Energy stored in its magnetic field is [CBSE PMT 1992; KCET 1998]
Options:
A) 0.5 J
B) 1 J
C) 0.05 J
D) 0.1 J
Show Answer
Answer:
Correct Answer: C
Solution:
Energy $ =\frac{1}{2}LI^{2}=\frac{1}{2}\times 100\times {{10}^{-3}}\times 1^{2}=0.05J $
