Electro Magnetic Induction And Alternating Currents Question 508

Question: In a coil of resistance 100 Q, a current is induced by changing the magnetic flux through it as . The magnitude of change in flux through the coil is

Options:

A) 250 Wb

B) 275 Wb

C) 200 Wb

D) 225 Wb

Show Answer

Answer:

Correct Answer: A

Solution:

  • According to Faraday’s law of electromagnetic induction,

    $ \varepsilon =\frac{d\phi }{dt} $ Also, $ \varepsilon =iR $
    $ \therefore iR=\frac{d\phi }{dt}\Rightarrow \int{d\phi =R\int{idt}} $

    Magnitude of change in flux $ (d\phi )=R\times area $ under current vs time graph or

    $ d\phi =100\times \frac{1}{2}\times \frac{1}{2}\times 10=250,Wb $



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