Electro Magnetic Induction And Alternating Currents Question 508
Question: In a coil of resistance 100 Q, a current is induced by changing the magnetic flux through it as . The magnitude of change in flux through the coil is
Options:
A) 250 Wb
B) 275 Wb
C) 200 Wb
D) 225 Wb
Show Answer
Answer:
Correct Answer: A
Solution:
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According to Faraday’s law of electromagnetic induction,
$ \varepsilon =\frac{d\phi }{dt} $ Also, $ \varepsilon =iR $
$ \therefore iR=\frac{d\phi }{dt}\Rightarrow \int{d\phi =R\int{idt}} $Magnitude of change in flux $ (d\phi )=R\times area $ under current vs time graph or
$ d\phi =100\times \frac{1}{2}\times \frac{1}{2}\times 10=250,Wb $
