Electro Magnetic Induction And Alternating Currents Question 493

Question: When the current in a certain inductor coil is 5.0 A and is increasing at the rate of 10.0 A/s, the potential difference across the coil is 140V. When the current is 5.0 A and decreasing at the rate of 10.0 A/s, the potential difference is 60V. The self-inductance of the coil is -

Options:

A) 2H

B) 4H

C) 8H

D) 12H

Show Answer

Answer:

Correct Answer: B

Solution:

  • Using
    $ V_{A}-V_{B}=RI+L\frac{dI}{dt}\Rightarrow 140=5R+10L $ $ 60=5R-10L $

    $ \Rightarrow L=4H $



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