Electro Magnetic Induction And Alternating Currents Question 493
Question: When the current in a certain inductor coil is 5.0 A and is increasing at the rate of 10.0 A/s, the potential difference across the coil is 140V. When the current is 5.0 A and decreasing at the rate of 10.0 A/s, the potential difference is 60V. The self-inductance of the coil is -
Options:
A) 2H
B) 4H
C) 8H
D) 12H
Show Answer
Answer:
Correct Answer: B
Solution:
-
Using
$ V_{A}-V_{B}=RI+L\frac{dI}{dt}\Rightarrow 140=5R+10L $ $ 60=5R-10L $$ \Rightarrow L=4H $
