Electro Magnetic Induction And Alternating Currents Question 492

Question: Two coils, one primary of 500 turns and one secondary of 25 turns, are wound on an iron ring of mean diameter 20 cm and cross-sectional area $ 12cm^{2} $ . If the permeability of iron is 800, the mutual inductance is:

Options:

A) 0.48 H

B) 2.4 H

C) 0.12 H

D) 0.24 H

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Answer:

Correct Answer: D

Solution:

  • $ M=\frac{{\mu_{0}}{\mu_{r}}N_{1}N_{2}}{2R_{1}}A $
    $ =\frac{4\pi \times {{10}^{-4}}\times 800\times 500\times 25\times 12\times {{10}^{-4}}}{2\times 0.1}=0.24H $


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