Electro Magnetic Induction And Alternating Currents Question 492
Question: Two coils, one primary of 500 turns and one secondary of 25 turns, are wound on an iron ring of mean diameter 20 cm and cross-sectional area $ 12cm^{2} $ . If the permeability of iron is 800, the mutual inductance is:
Options:
A) 0.48 H
B) 2.4 H
C) 0.12 H
D) 0.24 H
Show Answer
Answer:
Correct Answer: D
Solution:
- $ M=\frac{{\mu_{0}}{\mu_{r}}N_{1}N_{2}}{2R_{1}}A $
$ =\frac{4\pi \times {{10}^{-4}}\times 800\times 500\times 25\times 12\times {{10}^{-4}}}{2\times 0.1}=0.24H $
