SATHEE: Electro Magnetic Induction And Alternating Currents Question 449

Electro Magnetic Induction And Alternating Currents Question 449

Question: A coil having n turns and resistance $R Ω$ . Is connected with a galvanometer of resistance $4 R, Ω$ . This combination is moved in time t second from a magnetic flux $ϕ_{1}$ weber to $ϕ_{2}$ weber. The induced current in the circuit is

Options:

A) $- \frac{ϕ_{2} - ϕ_{1}}{5, R n t}$

B) $- \frac{n (ϕ_{2} - ϕ_{1})}{5, R t}$

C) $- \frac{(ϕ_{2} - ϕ_{1})}{, R n t}$

D) $- \frac{n (ϕ_{2} - ϕ_{1})}{, R t}$

Show Answer

Answer:

Correct Answer: B

Solution:

The change in flux $= n (ϕ_{2} - ϕ_{1})$

Total resistance of the circuit $= 4 R + R = 5 R$

Thus induced current, $i = \frac{Δ ϕ / Δ t}{R} = \frac{n (ϕ_{2} - ϕ_{1})}{5 R T}$

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Electro Magnetic Induction And Alternating Currents Question 449

Question: A coil having n turns and resistance RΩ . Is connected with a galvanometer of resistance 4R,Ω . This combination is moved in time t second from a magnetic flux ϕ1 weber to ϕ2 weber. The induced current in the circuit is

Options:

Answer:

Solution:

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Question: A coil having n turns and resistance $R Ω$ . Is connected with a galvanometer of resistance $4 R, Ω$ . This combination is moved in time t second from a magnetic flux $ϕ_{1}$ weber to $ϕ_{2}$ weber. The induced current in the circuit is