Electro Magnetic Induction And Alternating Currents Question 449
Question: A coil having n turns and resistance $ R\Omega $ . Is connected with a galvanometer of resistance $ 4R,\Omega $ . This combination is moved in time t second from a magnetic flux $ {\phi_{1}} $ weber to $ {\phi_{2}} $ weber. The induced current in the circuit is
Options:
A) $ -\frac{{\phi_{2}}-{\phi_{1}}}{5,Rnt} $
B) $ -\frac{n({\phi_{2}}-{\phi_{1}})}{5,Rt} $
C) $ -\frac{({\phi_{2}}-{\phi_{1}})}{,Rnt} $
D) $ -\frac{n({\phi_{2}}-{\phi_{1}})}{,Rt} $
Show Answer
Answer:
Correct Answer: B
Solution:
- The change in flux $ =n({\phi_{2}}-{\phi_{1}}) $
Total resistance of the circuit $ =4R+R=5R $
Thus induced current, $ i=\frac{\Delta \phi /\Delta t}{R}=\frac{n({\phi_{2}}-{\phi_{1}})}{5RT} $
