Electro Magnetic Induction And Alternating Currents Question 438

Question: A straight conductor of length 0.4 m is moved with a speed of 7 m/s perpendicular to the magnetic field of intensity of 0.9 Wb/m2. The induced e.m.f. across the conductor will be [MH CET (Med.) 1999]

Options:

A) 7.25 V

B) 3.75 V

C) 1.25 V

D) 2.52 V

Show Answer

Answer:

Correct Answer: D

Solution:

$ e=Bvl\Rightarrow e=0.9\times 7\times 0.4=2.52\ V $



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