Electro Magnetic Induction And Alternating Currents Question 438
Question: A straight conductor of length 0.4 m is moved with a speed of 7 m/s perpendicular to the magnetic field of intensity of 0.9 Wb/m2. The induced e.m.f. across the conductor will be [MH CET (Med.) 1999]
Options:
A) 7.25 V
B) 3.75 V
C) 1.25 V
D) 2.52 V
Show Answer
Answer:
Correct Answer: D
Solution:
$ e=Bvl\Rightarrow e=0.9\times 7\times 0.4=2.52\ V $
