Electro Magnetic Induction And Alternating Currents Question 421
Question: A 10 metre wire kept in east-west falling with velocity 5 m/sec perpendicular to the field $ 0.3\times {{10}^{-4}}Wb/m^{2} $ . The induced e.m.f. across the terminal will be [MP PET 2000]
Options:
A) 0.15 V
B) 1.5 mV
C) 1.5 V
D) 15.0 V
Show Answer
Answer:
Correct Answer: B
Solution:
Induced e.m.f. $ =Blv=0.3\times {{10}^{-4}}\times 10\times 5 $ $ =1.5\times {{10}^{-3}}V=1.5\ mV $
