Electro Magnetic Induction And Alternating Currents Question 421

Question: A 10 metre wire kept in east-west falling with velocity 5 m/sec perpendicular to the field $ 0.3\times {{10}^{-4}}Wb/m^{2} $ . The induced e.m.f. across the terminal will be [MP PET 2000]

Options:

A) 0.15 V

B) 1.5 mV

C) 1.5 V

D) 15.0 V

Show Answer

Answer:

Correct Answer: B

Solution:

Induced e.m.f. $ =Blv=0.3\times {{10}^{-4}}\times 10\times 5 $ $ =1.5\times {{10}^{-3}}V=1.5\ mV $



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