SATHEE: Electro Magnetic Induction And Alternating Currents Question 392

Electro Magnetic Induction And Alternating Currents Question 392

Question: A coil has 1,000 turns and 500 cm2 as its area. The plane of the coil is placed at right angles to a magnetic induction field of $2 \times 10^{- 5}, W b / m^{2}$ . The coil is rotated through $180^{o}$ in 0.2 seconds. The average e.m.f. induced in the coil, in milli-volts, is [EAMCET 2003]

Options:

A) 5

B) 10

C) 15

D) 20

Show Answer

Answer:

Correct Answer: B

Solution:

By using $e = - \frac{N B A (\cos θ_{2} - \cos θ_{1})}{Δ t}$ $e = - \frac{1000 \times 2 \times 10^{- 5} \times 500 \times 10^{- 4} (\cos 180^{o} - \cos 0^{o})}{0.2}$ $= 10^{- 2} v o l t = 10 m V$

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Electro Magnetic Induction And Alternating Currents Question 392

Question: A coil has 1,000 turns and 500 cm2 as its area. The plane of the coil is placed at right angles to a magnetic induction field of 2×10−5,Wb/m2 . The coil is rotated through 180o in 0.2 seconds. The average e.m.f. induced in the coil, in milli-volts, is [EAMCET 2003]

Options:

Answer:

Solution:

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