Electro Magnetic Induction And Alternating Currents Question 392

Question: A coil has 1,000 turns and 500 cm2 as its area. The plane of the coil is placed at right angles to a magnetic induction field of $ 2\times {{10}^{-5}},Wb/m^{2} $ . The coil is rotated through $ 180^{o} $ in 0.2 seconds. The average e.m.f. induced in the coil, in milli-volts, is [EAMCET 2003]

Options:

A) 5

B) 10

C) 15

D) 20

Show Answer

Answer:

Correct Answer: B

Solution:

By using $ e=-\frac{NBA( \cos {\theta_{2}}-\cos {\theta_{1}} )}{\Delta t} $ $ e=-\frac{1000\times 2\times {{10}^{-5}}\times 500\times {{10}^{-4}}( \cos 180^{o}-\cos 0^{o} )}{0.2} $ $ ={{10}^{-2}}volt=10mV $



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