Electro Magnetic Induction And Alternating Currents Question 315
Question: Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation $ I=I_{0}\sin \omega ,t $ , where $ I_{0}=10A $ and w = 100 p radian/sec. The maximum value of e.m.f. in the second coil is [CBSE PMT 1998; Pb. PMT 2000]
Options:
A) 2p
B) 5p
C) p
D) 4p
Show Answer
Answer:
Correct Answer: B
Solution:
$ e=M\frac{di}{dt}=0.005\times \frac{d}{dt}(i_{0}\sin \omega t) $ $ =0.005\times i_{0}\omega \cos \omega ,t $
$ \therefore {e_{\max }}=0.005\times 10\times 100\pi =5\pi $
