SATHEE: Electro Magnetic Induction And Alternating Currents Question 315

Electro Magnetic Induction And Alternating Currents Question 315

Question: Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation $I = I_{0} \sin ω, t$ , where $I_{0} = 10 A$ and w = 100 p radian/sec. The maximum value of e.m.f. in the second coil is [CBSE PMT 1998; Pb. PMT 2000]

Options:

A) 2p

B) 5p

C) p

D) 4p

Show Answer

Answer:

Correct Answer: B

Solution:

$e = M \frac{d i}{d t} = 0.005 \times \frac{d}{d t} (i_{0} \sin ω t)$ $= 0.005 \times i_{0} ω \cos ω, t$
$∴ e_{max} = 0.005 \times 10 \times 100 π = 5 π$

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Electro Magnetic Induction And Alternating Currents Question 315

Question: Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation I=I0sin⁡ω,t , where I0=10A and w = 100 p radian/sec. The maximum value of e.m.f. in the second coil is [CBSE PMT 1998; Pb. PMT 2000]

Options:

Answer:

Solution:

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Question: Two coils have a mutual inductance 0.005 H. The current changes in the first coil according to equation $I = I_{0} \sin ω, t$ , where $I_{0} = 10 A$ and w = 100 p radian/sec. The maximum value of e.m.f. in the second coil is [CBSE PMT 1998; Pb. PMT 2000]