Electro Magnetic Induction And Alternating Currents Question 26

Question: If resistance of 100 W , inductance of 0.5 henry and capacitance of $ 10\times {{10}^{-6}}F $ are connected in series through 50 Hz ac supply, then impedance is [BHU 1995]

Options:

A) 1.876

B) 18.76

C) 189.72

D) 101.3

Show Answer

Answer:

Correct Answer: C

Solution:

$ Z=\sqrt{R^{2}+{{(X_{L}-X_{C})}^{2}}} $ $ =\sqrt{100^{2}+{{( 0.5\times 100\pi -\frac{1}{10\times {{10}^{-6}}\times 100\pi } )}^{2}}} $ $ =189.72\Omega $



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