Electro Magnetic Induction And Alternating Currents Question 26

Question: If resistance of 100 W , inductance of 0.5 henry and capacitance of 10×106F are connected in series through 50 Hz ac supply, then impedance is [BHU 1995]

Options:

A) 1.876

B) 18.76

C) 189.72

D) 101.3

Show Answer

Answer:

Correct Answer: C

Solution:

Z=R2+(XLXC)2 =1002+(0.5×100π110×106×100π)2 =189.72Ω



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