Electro Magnetic Induction And Alternating Currents Question 26
Question: If resistance of 100 W , inductance of 0.5 henry and capacitance of $ 10\times {{10}^{-6}}F $ are connected in series through 50 Hz ac supply, then impedance is [BHU 1995]
Options:
A) 1.876
B) 18.76
C) 189.72
D) 101.3
Show Answer
Answer:
Correct Answer: C
Solution:
$ Z=\sqrt{R^{2}+{{(X_{L}-X_{C})}^{2}}} $ $ =\sqrt{100^{2}+{{( 0.5\times 100\pi -\frac{1}{10\times {{10}^{-6}}\times 100\pi } )}^{2}}} $ $ =189.72\Omega $
