Electro Magnetic Induction And Alternating Currents Question 163

Question: Resonance frequency of a circuit is f. If the capacitance is made 4 times the initial value, the resonance frequency will become :

Options:

A) $ f/2 $

B) 2f

C) f

D) f/4

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Answer:

Correct Answer: A

Solution:

  • $ f=\frac{1}{2\pi \sqrt{LC}}, $ i.e. $ f\propto \frac{1}{\sqrt{C}}\to \frac{1}{\sqrt{4}}=\frac{1}{2} $ time


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