Electro Magnetic Induction And Alternating Currents Question 163
Question: Resonance frequency of a circuit is f. If the capacitance is made 4 times the initial value, the resonance frequency will become :
Options:
A) $ f/2 $
B) 2f
C) f
D) f/4
Show Answer
Answer:
Correct Answer: A
Solution:
- $ f=\frac{1}{2\pi \sqrt{LC}}, $ i.e. $ f\propto \frac{1}{\sqrt{C}}\to \frac{1}{\sqrt{4}}=\frac{1}{2} $ time
