Electro Magnetic Induction And Alternating Currents Question 107

Question: A 280 ohm electric bulb is connected to 200V electric line. The peak value of current in the bulb will be [MP PET 2002]

Options:

A) About one ampere

B) Zero

C) About two ampere

D) About four ampere

Show Answer

Answer:

Correct Answer: A

Solution:

$ i_{rms}=\frac{200}{280}=\frac{5}{7}A. $ So $ i_{0}=i_{rms}\times \sqrt{2}=\frac{5}{7}\times \sqrt{2}\approx 1A. $



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