Electro Magnetic Induction And Alternating Currents Question 107
Question: A 280 ohm electric bulb is connected to 200V electric line. The peak value of current in the bulb will be [MP PET 2002]
Options:
A) About one ampere
B) Zero
C) About two ampere
D) About four ampere
Show Answer
Answer:
Correct Answer: A
Solution:
$ i_{rms}=\frac{200}{280}=\frac{5}{7}A. $ So $ i_{0}=i_{rms}\times \sqrt{2}=\frac{5}{7}\times \sqrt{2}\approx 1A. $
