Atoms And Nuclei Question 99

Question: The ratio of minimum to maximum wavelength in Balmer series is [MP PET 2000]

Options:

A) 5 : 9

B) 5 : 36

C) 1 : 4

D) 3 : 4

Show Answer

Answer:

Correct Answer: A

Solution:

$ \frac{1}{\lambda }=R[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} ]\Rightarrow \frac{{\lambda_{\min }}}{{\lambda_{\max }}}=\frac{[ \frac{1}{2^{2}}-\frac{1}{3^{2}} ]}{[ \frac{1}{2^{2}}-\frac{1}{\infty } ]}=\frac{5}{9} $



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