Atoms And Nuclei Question 99
Question: The ratio of minimum to maximum wavelength in Balmer series is [MP PET 2000]
Options:
A) 5 : 9
B) 5 : 36
C) 1 : 4
D) 3 : 4
Show Answer
Answer:
Correct Answer: A
Solution:
$ \frac{1}{\lambda }=R[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} ]\Rightarrow \frac{{\lambda_{\min }}}{{\lambda_{\max }}}=\frac{[ \frac{1}{2^{2}}-\frac{1}{3^{2}} ]}{[ \frac{1}{2^{2}}-\frac{1}{\infty } ]}=\frac{5}{9} $
