Atoms And Nuclei Question 67

Question: The ionisation energy of hydrogen atom is 13.6 eV. Following Bohr’s theory, the energy corresponding to a transition between the 3rd and the 4th orbit is [CBSE PMT 1992; DPMT 2000; RPMT 1999; AMU (Med.) 2001]

Options:

A) 3.40 eV

B) 1.51 eV

C) 0.85 eV

D) 0.66 eV

Show Answer

Answer:

Correct Answer: D

Solution:

$ E_{3}=-\frac{13.6}{9}=-1.51\ eV; $ $ E_{4}=-\frac{13.6}{16}=-0.85\ eV $
$ \therefore E_{4}-E_{3}=0.66\ eV $



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