Atoms And Nuclei Question 67
Question: The ionisation energy of hydrogen atom is 13.6 eV. Following Bohr’s theory, the energy corresponding to a transition between the 3rd and the 4th orbit is [CBSE PMT 1992; DPMT 2000; RPMT 1999; AMU (Med.) 2001]
Options:
A) 3.40 eV
B) 1.51 eV
C) 0.85 eV
D) 0.66 eV
Show Answer
Answer:
Correct Answer: D
Solution:
$ E_{3}=-\frac{13.6}{9}=-1.51\ eV; $ $ E_{4}=-\frac{13.6}{16}=-0.85\ eV $
$ \therefore E_{4}-E_{3}=0.66\ eV $
