Atoms And Nuclei Question 443

Question: The energy of a hydrogen atom in its ground state is $ -13.6\ eV $ . The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is

Options:

A) - 2.72 eV

B) - 0.85 eV

C) - 0.54 eV

D) - 3.4 eV

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Answer:

Correct Answer: D

Solution:

  • $ E_{n}=\frac{-13.6}{n^{2}}=\frac{-13.6}{4}=-3.4eV $


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