Atoms And Nuclei Question 443
Question: The energy of a hydrogen atom in its ground state is $ -13.6\ eV $ . The energy of the level corresponding to the quantum number n = 2 (first excited state) in the hydrogen atom is
Options:
A) - 2.72 eV
B) - 0.85 eV
C) - 0.54 eV
D) - 3.4 eV
Show Answer
Answer:
Correct Answer: D
Solution:
- $ E_{n}=\frac{-13.6}{n^{2}}=\frac{-13.6}{4}=-3.4eV $
