Atoms And Nuclei Question 437

Question: The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to

Options:

A) $ 13.6\ eV $

B) $ +\frac{13.6}{9}eV $

C) $ -\frac{13.6}{3}eV $

D) $ -\frac{3}{13.6}eV $

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Answer:

Correct Answer: B

Solution:

  • Energy required to knock out the electron in the nth orbit $ =+\frac{13.6}{n^{2}}eV $
    Þ $ E_{3}=+\frac{13.6}{9}eV $ .


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