Atoms And Nuclei Question 437
Question: The energy required to knock out the electron in the third orbit of a hydrogen atom is equal to
Options:
A) $ 13.6\ eV $
B) $ +\frac{13.6}{9}eV $
C) $ -\frac{13.6}{3}eV $
D) $ -\frac{3}{13.6}eV $
Show Answer
Answer:
Correct Answer: B
Solution:
- Energy required to knock out the electron in the nth orbit $ =+\frac{13.6}{n^{2}}eV $
Þ $ E_{3}=+\frac{13.6}{9}eV $ .
