Atoms And Nuclei Question 433
Question: Orbital acceleration of electron is
Options:
A) $ \frac{n^{2}h^{2}}{4{{\pi }^{2}}m^{2}r^{3}} $
B) $ \frac{n^{2}h^{2}}{2n^{2}r^{3}} $
C) $ \frac{4n^{2}h^{2}}{{{\pi }^{2}}m^{2}r^{3}} $
D) $ \frac{4n^{2}h^{2}}{4{{\pi }^{2}}m^{2}r^{3}} $
Show Answer
Answer:
Correct Answer: A
Solution:
- $ mvr=\frac{nh}{2\pi } $
Þ $ v=\frac{nh}{2\pi mr} $
Þ $ \frac{v^{2}}{r}=\frac{n^{2}h^{2}}{4{{\pi }^{2}}m^{2}r^{3}} $ .
