Atoms And Nuclei Question 433

Question: Orbital acceleration of electron is

Options:

A) $ \frac{n^{2}h^{2}}{4{{\pi }^{2}}m^{2}r^{3}} $

B) $ \frac{n^{2}h^{2}}{2n^{2}r^{3}} $

C) $ \frac{4n^{2}h^{2}}{{{\pi }^{2}}m^{2}r^{3}} $

D) $ \frac{4n^{2}h^{2}}{4{{\pi }^{2}}m^{2}r^{3}} $

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Answer:

Correct Answer: A

Solution:

  • $ mvr=\frac{nh}{2\pi } $
    Þ $ v=\frac{nh}{2\pi mr} $
    Þ $ \frac{v^{2}}{r}=\frac{n^{2}h^{2}}{4{{\pi }^{2}}m^{2}r^{3}} $ .


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