Atoms And Nuclei Question 341

Question: The mass of $ _{7}N^{15} $ is 15.00011 amu, mass of $ _{8}O^{16} $ is 15.99492 amu and $ mp=1.00783amu $ Determine binding energy of last proton of $ _{8}O^{16} $ .

Options:

A) 2.13 MeV

B) 0.13 MeV

C) 10 MeV

D) 12.13 MeV

Show Answer

Answer:

Correct Answer: D

Solution:

  • $ M{( _{8}}O^{16})=M{( _{7}}N^{15})+1m _{P} $

binding energy of last proton $ =M(N^{15})+m _{P}-M{( _{1}}O^{16}) $

$ =15.00011+1.00783-15.99492 $

$ =0.01302amu=12.13MeV $



NCERT Chapter Video Solution

Dual Pane