Atoms And Nuclei Question 341
Question: The mass of $ _{7}N^{15} $ is 15.00011 amu, mass of $ _{8}O^{16} $ is 15.99492 amu and $ mp=1.00783amu $ Determine binding energy of last proton of $ _{8}O^{16} $ .
Options:
A) 2.13 MeV
B) 0.13 MeV
C) 10 MeV
D) 12.13 MeV
Show Answer
Answer:
Correct Answer: D
Solution:
- $ M{( _{8}}O^{16})=M{( _{7}}N^{15})+1m _{P} $
binding energy of last proton $ =M(N^{15})+m _{P}-M{( _{1}}O^{16}) $
$ =15.00011+1.00783-15.99492 $
$ =0.01302amu=12.13MeV $
