Atoms And Nuclei Question 240
Question: The energy liberated on complete fission of 1 kg of $ _{92}U^{235} $ is (Assume 200 MeV energy is liberated on fission of 1 nucleus) [UPSEAT 2003]
Options:
A) $ 8.2\times 10^{10}J $
B) $ 8.2\times 10^{9}J $
C) $ 8.2\times 10^{13}J $
D) $ 8.2\times 10^{16}J $
Show Answer
Answer:
Correct Answer: C
Solution:
Mass of a uranium nucleus
$ =92\times 1.6725\times {{10}^{-27}}+143\times 1.6747\times {{10}^{-27}} $
$ =393.35\times {{10}^{-27}}kg $ Number of nuclei in the given mass
$ =\frac{1}{393.35\times {{10}^{-27}}}=2.542\times 10^{24} $
Energy released $=200\times 2.542\times 10^{24}MeV $
$ =5.08\times 10^{26}MeV=8.135\times 10^{13}J=8.2\times 10^{13}J $
