SATHEE: Atoms And Nuclei Question 240

Atoms And Nuclei Question 240

Question: The energy liberated on complete fission of 1 kg of $_{92} U^{235}$ is (Assume 200 MeV energy is liberated on fission of 1 nucleus) [UPSEAT 2003]

Options:

A) $8.2 \times 10^{10} J$

B) $8.2 \times 10^{9} J$

C) $8.2 \times 10^{13} J$

D) $8.2 \times 10^{16} J$

Show Answer

Answer:

Correct Answer: C

Solution:

Mass of a uranium nucleus

$= 92 \times 1.6725 \times 10^{- 27} + 143 \times 1.6747 \times 10^{- 27}$

$= 393.35 \times 10^{- 27} k g$ Number of nuclei in the given mass

$= \frac{1}{393.35 \times 10^{- 27}} = 2.542 \times 10^{24}$

Energy released $= 200 \times 2.542 \times 10^{24} M e V$

$= 5.08 \times 10^{26} M e V = 8.135 \times 10^{13} J = 8.2 \times 10^{13} J$

Atoms And Nuclei Question 240

Question: The energy liberated on complete fission of 1 kg of $_{92} U^{235}$ is (Assume 200 MeV energy is liberated on fission of 1 nucleus) [UPSEAT 2003]

Options:

Answer:

Solution:

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Atoms And Nuclei Question 240

Question: The energy liberated on complete fission of 1 kg of 92U235 is (Assume 200 MeV energy is liberated on fission of 1 nucleus) [UPSEAT 2003]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The energy liberated on complete fission of 1 kg of $_{92} U^{235}$ is (Assume 200 MeV energy is liberated on fission of 1 nucleus) [UPSEAT 2003]