Atoms And Nuclei Question 237
Question: In the nuclear reaction: $ X(n,,\alpha ) _{3}Li^{7} $ the term X will be 3 [CBSE PMT 2001; AIEEE 2005]
Options:
A) $ _{5}B^{10} $
B) $ _{5}B^{9} $
C) $ _{5}B^{11} $
D) $ _{2}He^{4} $
Show Answer
Answer:
Correct Answer: A
Solution:
$ Xn \alpha _{3}^{7}Li\rightarrow _{Z}X^{A}+ _{0}n^{1} \to 3Li^{7}+ _{2}He^{4}$
$ Z=3+2=5 $ and A= 7+4 ? 1 =10
$ {\therefore_{5}}X^{10}{=_{5}}B^{10} $
