Atoms And Nuclei Question 237

Question: In the nuclear reaction: $ X(n,,\alpha ) _{3}Li^{7} $ the term X will be 3 [CBSE PMT 2001; AIEEE 2005]

Options:

A) $ _{5}B^{10} $

B) $ _{5}B^{9} $

C) $ _{5}B^{11} $

D) $ _{2}He^{4} $

Show Answer

Answer:

Correct Answer: A

Solution:

$ Xn \alpha _{3}^{7}Li\rightarrow _{Z}X^{A}+ _{0}n^{1} \to 3Li^{7}+ _{2}He^{4}$

$ Z=3+2=5 $ and A= 7+4 ? 1 =10

$ {\therefore_{5}}X^{10}{=_{5}}B^{10} $



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