Atoms And Nuclei Question 176

Question: If the binding energy per nucleon in Li7 and He4 nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction Li7+p2 2He4 is [CBSE PMT 1994; JIPMER 2000]

Options:

A) 19.6 MeV

B) 2.4 MeV

C) 8.4 MeV

D) 17.3 MeV

Show Answer

Answer:

Correct Answer: D

Solution:

B.E. of Li7=39.20 MeV and He4=28.24 MeV

Hence binding energy of 2He4=56.48 MeV

Energy of reaction =56.4839.20=17.28 MeV .



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