Atoms And Nuclei Question 176

Question: If the binding energy per nucleon in $ Li^{7} $ and $ He^{4} $ nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction $ Li^{7}+p\to 2{\ _{2}}He^{4} $ is [CBSE PMT 1994; JIPMER 2000]

Options:

A) 19.6 MeV

B) 2.4 MeV

C) 8.4 MeV

D) 17.3 MeV

Show Answer

Answer:

Correct Answer: D

Solution:

B.E. of $ Li^{7}=39.20\ MeV $ and $ He^{4}=28.24\ MeV $

Hence binding energy of $ 2He^{4}=56.48\ MeV $

Energy of reaction $ =56.48-39.20=17.28\ MeV $ .



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