Atoms And Nuclei Question 176
Question: If the binding energy per nucleon in $ Li^{7} $ and $ He^{4} $ nuclei are respectively 5.60 MeV and 7.06 MeV, then energy of reaction $ Li^{7}+p\to 2{\ _{2}}He^{4} $ is [CBSE PMT 1994; JIPMER 2000]
Options:
A) 19.6 MeV
B) 2.4 MeV
C) 8.4 MeV
D) 17.3 MeV
Show Answer
Answer:
Correct Answer: D
Solution:
B.E. of $ Li^{7}=39.20\ MeV $ and $ He^{4}=28.24\ MeV $
Hence binding energy of $ 2He^{4}=56.48\ MeV $
Energy of reaction $ =56.48-39.20=17.28\ MeV $ .
