Some Basic Concepts Of Chemistry Question 87

Question: If potassium chlorate is 80% pure, then 48 g of oxygen would be produced from (atomic mass of K=39)

Options:

A) 153.12 g of $ KClO _3 $

B) 122.5 g of $ KClO _3 $

C) 245 g of $ KClO _3 $

D) 98 g of $ KClO _3 $

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ \underset{\begin{smallmatrix} 2\times 122.5g \\ ,245 \end{smallmatrix}}{\mathop{2KClO _3}},\xrightarrow{^{heat}}2KCl+\underset{\begin{smallmatrix} 3\times 32g \\ ,96 \end{smallmatrix}}{\mathop{3O _2}}, $ 48 g of oxygen will be produced from 122.5 g of $ KClO _3 $
$ \therefore $ Amount of 80% $ KClO _3 $ needed $ =\frac{100}{80}\times 122.5=153.12g $



NCERT Chapter Video Solution

Dual Pane