Some Basic Concepts Of Chemistry Question 87

Question: If potassium chlorate is 80% pure, then 48 g of oxygen would be produced from (atomic mass of K=39)

Options:

A) 153.12 g of KClO3

B) 122.5 g of KClO3

C) 245 g of KClO3

D) 98 g of KClO3

Show Answer

Answer:

Correct Answer: A

Solution:

[a] 2KClO32×122.5g,245,heat2KCl+3O23×32g,96, 48 g of oxygen will be produced from 122.5 g of KClO3
Amount of 80% KClO3 needed =10080×122.5=153.12g



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