Some Basic Concepts Of Chemistry Question 85

Question: 1 g mixture of equal number of mole of $ Li _2CO _3 $ and other metal carbonate $ (M _2CO _3) $ required 21.6 mL of $ 0.5NHCl $ for complete neutralization reaction. What is the approximate atomic mass of the other metal?

Options:

A) 25

B) 23

C) 51

D) 118

Show Answer

Answer:

Correct Answer: D

Solution:

[d] Let x g of $ Li _2CO _3 $ and $ ( 1-x )g $ of $ M _2CO _3 $ present in given mixture $ 2\times $ Total moles of carbonates = moles of HCl and $ 2\times ( \frac{x}{74}+\frac{1-x}{2M+60} )=21.6\times 0.5\times {10^{-3}} $ $ x=0.20 $
$ \therefore \frac{x}{74}=\frac{1-x}{2M+60} $ $ M=118 $



NCERT Chapter Video Solution

Dual Pane