Some Basic Concepts Of Chemistry Question 85
Question: 1 g mixture of equal number of mole of $ Li _2CO _3 $ and other metal carbonate $ (M _2CO _3) $ required 21.6 mL of $ 0.5NHCl $ for complete neutralization reaction. What is the approximate atomic mass of the other metal?
Options:
A) 25
B) 23
C) 51
D) 118
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Let x g of $ Li _2CO _3 $ and $ ( 1-x )g $ of $ M _2CO _3 $ present in given mixture $ 2\times $ Total moles of carbonates = moles of HCl and $ 2\times ( \frac{x}{74}+\frac{1-x}{2M+60} )=21.6\times 0.5\times {10^{-3}} $ $ x=0.20 $
$ \therefore \frac{x}{74}=\frac{1-x}{2M+60} $ $ M=118 $
