Some Basic Concepts Of Chemistry Question 79

Question: 10 moles $ SO _2 $ and 15 moles $ O _2 $ were allowed to react over a suitable catalyst. 8 moles of $ SO _3 $ were formed. The remaining moles of $ SO _2 $ and $ O _2 $ respectively are-

Options:

A) 2 moles, 11 moles

B) 2 moles, 8 moles

C) 4 moles, 5 moles

D) 8 moles, 2 moles

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $ \underset{10}{\mathop{2SO _2}},+\underset{15}{\mathop{O _2}},\xrightarrow{{}}\underset{0}{\mathop{2SO _3}}, $

$ 10-2x~~~~~~~15-x~~~~~2x $

$ \therefore 2x=8,c=4 $ Hence, remaining, $ SO _2=10-8=2 $ moles, $ O _2=15-4=11 $ moles



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